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//Chapter-1,Example 1_25,Page 1-47
clc()
//Given Data:
lam1=6*10^-7 //wavelength of light
lam2=4.5*10^-7 //wavelength of light
R=0.9 //Radius of curvature
//Calculations:
//As Dn^2=4*n*R*lam.
//Dn^2=D(n+1)^2 for different wavelengths.we get,
n=lam2/(lam1-lam2) //nth dark ring due to lam1 which coincides with (n+1)th dark ring due lam2
D3=sqrt(4*n*R*lam1) //diameter of 3rd dark ring for lam1
printf('Diameter of 3rd dark ring for lam1 is =%.5f m \n',D3)
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