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+//Chapter-1,Example 1_25,Page 1-47
+clc()
+
+//Given Data:
+lam1=6*10^-7     //wavelength of light
+lam2=4.5*10^-7   //wavelength of light
+R=0.9            //Radius of curvature
+
+//Calculations:
+//As Dn^2=4*n*R*lam.
+//Dn^2=D(n+1)^2 for different wavelengths.we get,
+n=lam2/(lam1-lam2)    //nth dark ring due to lam1 which coincides with (n+1)th dark ring due lam2
+D3=sqrt(4*n*R*lam1)   //diameter of 3rd dark ring for lam1
+printf('Diameter of 3rd dark ring for lam1 is =%.5f m \n',D3)