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clear all; clc;
disp("Scilab Code Ex 5.11 : ")
//Given:
d = 20/1000; //m
r = d/2;
l_bc = 0.2;
l_cd = 1.5;
l_da = 0.3;
T_c = 800; //Nm
T_d = -500; //Nm
//Equilibrium:
//Eqn 1 : 300 = T_a + T_b
//Compatibility:
//Eqn 2:
coeff_Tb = -l_bc;
coeff_Ta = l_cd + l_da;
//Solving Equations simultaneously using matrices:
C = [1 1; coeff_Tb coeff_Ta];
b = [300 ; -750];
T = C\b;
T_b = T(1);
T_a = T(2);
//Display:
printf('\n\nThe reaction at A = %1.0f Nm',T_a);
printf('\nThe reaction at B = %1.0f Nm',T_b);
//---------------------------------------------------------------------------------END--------------------------------------------------------------------
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