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// Example 13.12
// We know that E=4.44*f*N*Qm
Qm=0.06; // Megnetic flux
f=50; // Frequency
E2=250; // Voltage
N2=E2/(4.44*f*Qm); // No.Of of turns in 2ry coil
disp(' No.Of turns (N2) = '+string(round(N2))+' turns');
E1=5000; // Voltage
N1=(E1/E2)*19; // No.Of turns in 1ry coil
disp(' No.Of turns (N1) = '+string(N1)+' turns');
kVA=150*10^3; // kVA Rating
pf=1; // Power factor
Po=0.5*kVA*pf; // O/p power
Cfl=1800; // Full-load Copper losses
Pc=0.5*0.5*Cfl; // Copper losses
Pi=1500; // Iron losses
n=Po/(Po+Pc+Pi); // Efficiency
disp(' Efficiency at half kVA = '+string(n*100)+' %');
pf1=0.8; // Power factor
Po1=kVA*pf1; // O/p power
Pc1=1800; // Copper losses
n1=Po1/(Po1+Pc1+Pi); // Efficiency
disp(' Efficiency at Full-load & at(pf=0.8) = '+string(n1*100)+' %');
// We know that x^2 x 1800= 1500
x=sqrt(1500/1800); // Value of x
kVA1=kVA*x; // kVA Load for Maximum efficiency
disp(' kVA Load for Maximum efficiency = '+string(round(kVA1/1000))+' kVA');
// p 509 13.12
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