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//Chapter 2, Problem 6
clc;
V1=100; //Battery voltage
I1=5*10^-3; //Current of 5mA;
V2=25; //Voltage is now reduced to 25V
R=V1/I1; //Calculating resistance due to V1 using Ohms law
I2=V2/R; //Calculating current due to V2 using Ohms law
printf("Resistance of resistor = %d k.ohms\n\n\n",R/1000);
printf("Current when voltage is reduced to 25V = %f mA",I2*1000);
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