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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1529/CH2/EX2.6/2_06.sce | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '1529/CH2/EX2.6/2_06.sce')
| -rwxr-xr-x | 1529/CH2/EX2.6/2_06.sce | 9 |
1 files changed, 9 insertions, 0 deletions
diff --git a/1529/CH2/EX2.6/2_06.sce b/1529/CH2/EX2.6/2_06.sce new file mode 100755 index 000000000..f54bd79a7 --- /dev/null +++ b/1529/CH2/EX2.6/2_06.sce @@ -0,0 +1,9 @@ +//Chapter 2, Problem 6
+clc;
+V1=100; //Battery voltage
+I1=5*10^-3; //Current of 5mA;
+V2=25; //Voltage is now reduced to 25V
+R=V1/I1; //Calculating resistance due to V1 using Ohms law
+I2=V2/R; //Calculating current due to V2 using Ohms law
+printf("Resistance of resistor = %d k.ohms\n\n\n",R/1000);
+printf("Current when voltage is reduced to 25V = %f mA",I2*1000);
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