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//CHAPTER 4- MEASURING INSTRUMENTS
//Example 12
disp("CHAPTER 4");
disp("EXAMPLE 12");
//VARIABLE INITIALIZATION
I1=1; //full scale current in 1st ammeter in mA
I2=10; //full scale current in 2nd ammeter in mA
r1=100; //internal resistance of 1st ammeter in Ohms
r2=25; //internal resistance of 2nd ammeter in Ohms
//SOLUTION
R1=r2/(r1+r2); //resistance for 1st ammeter
R2=r1/(r1+r2); //resistance for 2nd ammeter
I=I1/R1; //by current divider law I1=(I*r2)/(r1+r2) =>I1=I*R1 =>I=I1/R1
A2=I*R2; //A2=reading of second ammeter
disp(sprintf("The total current that the two ammeters can carry is %d mA",I));
//END
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