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+//CHAPTER 4- MEASURING INSTRUMENTS
+//Example 12
+
+disp("CHAPTER 4");
+disp("EXAMPLE 12");
+
+//VARIABLE INITIALIZATION
+I1=1;               //full scale current in 1st ammeter in mA
+I2=10;              //full scale current in 2nd ammeter in mA
+r1=100;             //internal resistance of 1st ammeter in Ohms
+r2=25;              //internal resistance of 2nd ammeter in Ohms
+
+//SOLUTION
+R1=r2/(r1+r2);      //resistance for 1st ammeter 
+R2=r1/(r1+r2);      //resistance for 2nd ammeter
+I=I1/R1;            //by current divider law I1=(I*r2)/(r1+r2) =>I1=I*R1 =>I=I1/R1 
+A2=I*R2;            //A2=reading of second ammeter
+disp(sprintf("The total current that the two ammeters can carry is %d mA",I));
+
+//END
+
+