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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
//Example 5
clc;
disp("CHAPTER 2");
disp("EXAMPLE 5");
//VARIABLE INITIALIZATION
I1=0.75; //in Amperes
v=240; //in Volts
f=50; //in Hertz
p=80; //in Watts
//SOLUTION
res=p/v;
pf1=res/I1; //1st power factor = cos(Φ1)
phi1=acos(pf1);
res1=tan(phi1); //result1 = tan(Φ1)
w=2*%pi*f;
//solution (a)
res2=0; //result2 = tan(Φ2)
Ic1=res*(res1-res2);
c1=Ic1/(v*w);
disp(sprintf("(a) When power factor is unity, the value of capacitance is %f μF",c1*(10^6)));
//solution (b)
pf2=0.95; //given
phi2=acos(pf2);
res2=tan(phi2);
Ic2=res*(res1-res2);
c2=Ic2/(v*w);
disp(sprintf("(b) When power factor is 0.95(lagging), the value of capacitance is %f μF",c2*(10^6)));
//END
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