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-rw-r--r--1445/CH2/EX2.5/Ex2_5.sce26
1 files changed, 12 insertions, 14 deletions
diff --git a/1445/CH2/EX2.5/Ex2_5.sce b/1445/CH2/EX2.5/Ex2_5.sce
index ce799fefc..4fbe07d32 100644
--- a/1445/CH2/EX2.5/Ex2_5.sce
+++ b/1445/CH2/EX2.5/Ex2_5.sce
@@ -1,30 +1,28 @@
//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
//Example 5
+clc;
disp("CHAPTER 2");
disp("EXAMPLE 5");
//VARIABLE INITIALIZATION
-I1=0.75; //current in loop 1 in Amperes
-v=240; //voltage supply in Volts
-f=50; //frequency in Hertz
-p=80; //power consumed by the lamp in Watts
+I1=0.75; //in Amperes
+v=240; //in Volts
+f=50; //in Hertz
+p=80; //in Watts
//SOLUTION
-//V.I1.cos(Φ1) = P
-res=p/v; //I1cos(Φ1)
-pf1=res/I1; //1st power factor = cos(Φ1)
+res=p/v;
+pf1=res/I1; //1st power factor = cos(Φ1)
phi1=acos(pf1);
-res1=tan(phi1); //result1 = tan(Φ1)
-w=2*%pi*f; //w=2.pi.f
+res1=tan(phi1); //result1 = tan(Φ1)
+w=2*%pi*f;
//solution (a)
-//Given power factor = unity means cos(Φ2)=1
-//hence Φ2=0, tan (Φ2)=0
-res2=0; //result2 = tan(Φ2) as Φ2=0
+res2=0; //result2 = tan(Φ2)
Ic1=res*(res1-res2);
c1=Ic1/(v*w);
-disp(sprintf("(a) When power factor is unity, the value of capacitance is %4.2f μF",c1*(10^6))); // in mF
+disp(sprintf("(a) When power factor is unity, the value of capacitance is %f μF",c1*(10^6)));
//solution (b)
pf2=0.95; //given
@@ -32,7 +30,7 @@ phi2=acos(pf2);
res2=tan(phi2);
Ic2=res*(res1-res2);
c2=Ic2/(v*w);
-disp(sprintf("(b) When power factor is 0.95(lagging), the value of capacitance is %5.3f μF",c2*(10^6))); //textbook answer is 7.458 mF
+disp(sprintf("(b) When power factor is 0.95(lagging), the value of capacitance is %f μF",c2*(10^6)));
//END