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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
//Example 32 // read it as example 31 in the book on page 2.85
clc;
disp("CHAPTER 2");
disp("EXAMPLE 32");
//VARIABLE INITIALIZATION
//function of the waveform is deduced to be i=Im.sinΘ
//SOLUTION
//Iav=(1/2.π).Integral(ydΘ) from 0 to π, and π to 2.π is zero, interval is 2.π
//
//say
Im=1; // in Amp
Iav=(1/(2*%pi))*integrate('(Im*sin(th))', 'th', 0, %pi);
//disp(sprintf("The average value of waveform is %f", Iav));
//RMS mean square value (1/π).Integral(y^2.dΘ) from 0 to π
Ims=(1/(2*%pi))*integrate('(Im*sin(th))^2', 'th', 0, %pi);
//disp(sprintf("The RMS value of waveform is %f", sqrt(Ims)));
ff=sqrt(Ims)/Iav;
disp(sprintf("The form factor of waveform is %f",ff));
disp(" ");
//
//END
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