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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
//Example 22 // read it as example 22 in the book on page 2.76
disp("CHAPTER 2");
disp("EXAMPLE 23");
//VARIABLE INITIALIZATION
A=100 //Amplitude in Amps
f=50 //frquency in Hz
t1=1/600 //sec after wave becomes zero again
a1=86.6 //amplitude at some time t after start
//SOLUTION
//solution (a)
//RAmplitude at 1/600 second after it becomes zero
w=f*2*%pi; //angular speed
hp=1/(2*f); //half period, the point where sine beomes zero again after origin
t=hp+t1;
a2=A*sin(w*t);
disp("SOLUTION (a)");
disp(sprintf("Amplitude after 1/600 sec is %3f A", a2));
disp(" ");
//solution (b)
//since A=A0.sinwt, t=asin(A/A0)/w
t2=(asin(a1/A))/w;
disp("SOLUTION (b)");
disp(sprintf("The time at which amp would be %fis %3f sec", a1,t2));
//
//solution (iii)
//Bandwidth (f2-f1)=R/(2.π.L), f1,f2 half power frequencies
//
//END
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