//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT //Example 22 // read it as example 22 in the book on page 2.76 disp("CHAPTER 2"); disp("EXAMPLE 23"); //VARIABLE INITIALIZATION A=100 //Amplitude in Amps f=50 //frquency in Hz t1=1/600 //sec after wave becomes zero again a1=86.6 //amplitude at some time t after start //SOLUTION //solution (a) //RAmplitude at 1/600 second after it becomes zero w=f*2*%pi; //angular speed hp=1/(2*f); //half period, the point where sine beomes zero again after origin t=hp+t1; a2=A*sin(w*t); disp("SOLUTION (a)"); disp(sprintf("Amplitude after 1/600 sec is %3f A", a2)); disp(" "); //solution (b) //since A=A0.sinwt, t=asin(A/A0)/w t2=(asin(a1/A))/w; disp("SOLUTION (b)"); disp(sprintf("The time at which amp would be %fis %3f sec", a1,t2)); // //solution (iii) //Bandwidth (f2-f1)=R/(2.π.L), f1,f2 half power frequencies // //END