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clear;
clc;
// Stoichiometry
// Chapter 7
// Combustion
// Example 7.3
// Page 444
printf("Example 7.3, Page 444 \n \n");
// solution
// basis 1 mol of gaseous propane
H2O = 4*18.0153 //g
NHV = 2219.17-(H2O*2442.5/1000)
printf("NHV = "+string(NHV)+" kJ/mol.")
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