clear;
clc;

// Stoichiometry
// Chapter 7
// Combustion


// Example 7.3
// Page 444
printf("Example 7.3, Page 444 \n \n");

// solution

// basis 1 mol of gaseous propane
H2O = 4*18.0153  //g
NHV = 2219.17-(H2O*2442.5/1000)
printf("NHV = "+string(NHV)+" kJ/mol.")