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// Electric Machinery and Transformers
// Irving L kosow
// Prentice Hall of India
// 2nd editiom
// Chapter 2: Dynamo Construction and Windings
// Example 2-6
clear; clc; close; // Clear the work space and console.
// Given data
P = 4;// No. of poles
phi = 3; // No. of phases
slots_(1) = 12; // No. of slots for case 1
slots_(2) = 24; // No. of slots for case 2
slots_(3) = 48; // No. of slots for case 3
slots_(4) = 84; // No. of slots for case 4
// Calculations
electrical_degrees = 180 * 4;
i=1; // where i is case subscript .eg case1, case2, etc
while i<=4
alpha_(i) = electrical_degrees / slots_(i); // electrical degrees
// per slots for case i
n_(i) = slots_(i) / ( P * phi ); // No. of ac cycles for case 1
k_d(i) = sind( n_(i)*( alpha_(i) / 2 ) ) / ( n_(i) * sind( alpha_(i) / 2));
i=i+1;
end;
// Display the results
disp("Example 2-6 Solution : ")
printf("\n a:");
i=1; // where i is case subscript .eg case1, case2, etc
while i<=4
printf("\n \t %d: alpha = %.2f degrees/slot", i , alpha_(i) );
printf("\n\t n = %d slots/pole-phase ", n_(i) );
printf("\n\t kd = %.3f ", k_d(i));
printf("\n");
i=i+1;
end;
printf("\n\n\n b: ");
printf("\n \t \t n \t alpha in degrees \t\t kd ");
printf("\n \t __________________________________________________________" );
i=1;
while i<=4
printf("\n \t \t %d \t %.2f \t\t\t\t%.3f ", n_(i) , alpha_(i) , k_d(i) );
i = i +1;
end;
printf("\n \t __________________________________________________________" );
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