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+// Electric Machinery and Transformers
+// Irving L kosow 
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 2: Dynamo Construction and Windings
+// Example 2-6
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+P = 4;// No. of poles
+phi = 3; // No. of phases
+slots_(1) = 12; // No. of slots for case 1
+slots_(2) = 24; // No. of slots for case 2
+slots_(3) = 48; // No. of slots for case 3
+slots_(4) = 84; // No. of slots for case 4
+
+// Calculations
+electrical_degrees = 180 * 4;
+i=1; // where i is case subscript .eg case1, case2, etc
+
+  while i<=4  
+    alpha_(i) = electrical_degrees / slots_(i); // electrical degrees  
+    // per slots for case i
+    n_(i) = slots_(i) / ( P * phi ); // No. of ac cycles for case 1
+    k_d(i) = sind( n_(i)*( alpha_(i) / 2 ) ) / ( n_(i) * sind( alpha_(i) / 2));
+    i=i+1;
+  end;
+     
+// Display the results
+disp("Example 2-6 Solution : ")
+printf("\n a:");
+ i=1; // where i is case subscript .eg case1, case2, etc
+   
+   while i<=4
+        printf("\n \t %d: alpha = %.2f degrees/slot", i , alpha_(i) );
+        printf("\n\t    n = %d slots/pole-phase ", n_(i) );
+        printf("\n\t    kd = %.3f ", k_d(i));
+        printf("\n");
+        i=i+1; 
+   end;
+   
+printf("\n\n\n b: ");
+printf("\n \t \t n \t alpha in degrees  \t\t kd ");
+printf("\n \t __________________________________________________________" );
+i=1;
+
+ while i<=4
+    printf("\n \t \t %d \t %.2f \t\t\t\t%.3f ", n_(i) , alpha_(i) , k_d(i) );
+    i = i +1;
+  end;
+    printf("\n \t __________________________________________________________" );
+