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clc;
clear;
//Example 3.9
v=17.36*10^-6 //Viscosity for air [sq m./s]
k=0.0275 //for air ..[W/(m.K)]
Cp=1.006 //[kJ/(kg.K)]
Npr=0.7 //for air
u_inf=2 //[m/s]
x=0.2 //[m]
Nre_x=u_inf*x/v //Reynolds number at x=0.2 m
//Since this is less than 3*10^5
Nnu_x=0.332*sqrt(Nre_x)*(Npr^(1.0/3.0))
hx=Nnu_x*k/x //[W/(sq m.K]
//Average value of heat transfer coeff is twice this value
h=2*hx //[W/sq m.K)]
h=12.3 //Approximation
w=1 //width in [m]
A=x*w //[sq m] Area of plate
Tw=333 //[K]
T_inf=300 //[K]
Q=h*A*(Tw-T_inf) //Heat flow in [W]
printf("\nANSWER:\nHeat flow is :%f W\n",Q)
//From both sides of plate:
Q=2*Q //[W]
printf("\nANSWER\n Heat flow from both sides of plate is %f W",Q);
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