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+clear;
+clc;
+
+// Illustration 2.1
+// Page: 94
+
+printf('Illustration 2.1 -  Page: 94\n\n');
+
+// solution
+
+//*****Data*****//
+// a-oxygen   b-stagnant water
+T = 310; // [K]
+// Since the solubility of oxygen in water at 310 K is extremely low, we are dealing with dilute solutions
+k_L = 3.3*10^-5; // [coefficient based on the oxygen concentration difference in the water, m/s]
+row = 993; // [kg/cubic m]
+M_b = 18; // [gram/mole]
+//*****//
+ 
+// Since we are dealing with very dilute solutions
+// Therefore, c = (row/M_avg) = row/M_b
+c = row/M_b; // [kmole/cubic m]
+// Using equation 2.10
+k_x = k_L*c; // [kmole/square m.s]
+printf("The mass-transfer coefficient based on the mole fraction of oxygen in the liquid is %e kmole/square m.s\n\n",k_x);
+
+ 
+\ No newline at end of file