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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /905/CH2/EX2.1/2_1.sce | |
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initial commit / add all books
Diffstat (limited to '905/CH2/EX2.1/2_1.sce')
| -rwxr-xr-x | 905/CH2/EX2.1/2_1.sce | 27 |
1 files changed, 27 insertions, 0 deletions
diff --git a/905/CH2/EX2.1/2_1.sce b/905/CH2/EX2.1/2_1.sce new file mode 100755 index 000000000..edad20edf --- /dev/null +++ b/905/CH2/EX2.1/2_1.sce @@ -0,0 +1,27 @@ +clear;
+clc;
+
+// Illustration 2.1
+// Page: 94
+
+printf('Illustration 2.1 - Page: 94\n\n');
+
+// solution
+
+//*****Data*****//
+// a-oxygen b-stagnant water
+T = 310; // [K]
+// Since the solubility of oxygen in water at 310 K is extremely low, we are dealing with dilute solutions
+k_L = 3.3*10^-5; // [coefficient based on the oxygen concentration difference in the water, m/s]
+row = 993; // [kg/cubic m]
+M_b = 18; // [gram/mole]
+//*****//
+
+// Since we are dealing with very dilute solutions
+// Therefore, c = (row/M_avg) = row/M_b
+c = row/M_b; // [kmole/cubic m]
+// Using equation 2.10
+k_x = k_L*c; // [kmole/square m.s]
+printf("The mass-transfer coefficient based on the mole fraction of oxygen in the liquid is %e kmole/square m.s\n\n",k_x);
+
+
\ No newline at end of file |