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+//clear//
+clear;
+clc;
+
+//Exapmle 9.7
+//Given
+Dt = 2; //[m]
+Da = 0.667; //[m]
+n = 180/60; //[rps]
+T = 20; //[C]
+qg = 100; //[m^3/h]
+rho = 1000; //[kg/m^3]
+mu = 10^-3; //[kg/m-s] 
+ut = 0.2; //[m/s]
+At = %pi/4*Dt^2; //[m^2]
+//Using values form Example 7.6
+//Assuming Pg/Po decresaes to 0.25
+PgbyV = 0.25*20490/6.28; //[W/m^3]
+//Using Eq.(9.47)
+Vs_barc = 0.114*(PgbyV)*(Dt/1.5)^0.17/1000 //[m/s]
+qg = Vs_barc*At*3600 //[m^3/h]
+//The calculated flooding velocity is beyond the range of the data on which Eq.(9.47)
+//was based, so it may not be relaible. Based on Vs_barc, the highest measured value, qg
+//would be 850 m^3/h.