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+ 
+ Water is flowing through an open channel at a depth of 2 m and a velocity of 3m/s.it then flows through a contracting chute into another channel where the depth i 
+      s 1 m and the velocity is 10m/s.assuming frictionless flow,determine the difference in the elevation of the channel floors.                                   
+ 
+ Solution:   
+ 
+ The points 1 and 2 can be selected on the free surface and therefore p1=p2=0   
+ 
+ Therefore by bernoullis equation the difference in the elevation  of the channel is y=   
+ 
+    3.6381244  
+ 
+ m   
+ 
+-->exec('SCI/etc/scilab.quit','errcatch',-1);quit;