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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /806/CH4/EX4.5/45.txt | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '806/CH4/EX4.5/45.txt')
| -rw-r--r-- | 806/CH4/EX4.5/45.txt | 15 |
1 files changed, 15 insertions, 0 deletions
diff --git a/806/CH4/EX4.5/45.txt b/806/CH4/EX4.5/45.txt new file mode 100644 index 000000000..9717574b8 --- /dev/null +++ b/806/CH4/EX4.5/45.txt @@ -0,0 +1,15 @@ +
+ Water is flowing through an open channel at a depth of 2 m and a velocity of 3m/s.it then flows through a contracting chute into another channel where the depth i
+ s 1 m and the velocity is 10m/s.assuming frictionless flow,determine the difference in the elevation of the channel floors.
+
+ Solution:
+
+ The points 1 and 2 can be selected on the free surface and therefore p1=p2=0
+
+ Therefore by bernoullis equation the difference in the elevation of the channel is y=
+
+ 3.6381244
+
+ m
+
+-->exec('SCI/etc/scilab.quit','errcatch',-1);quit;
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