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+//Solution 11-5
+WD=get_absolute_file_path('11_06_solution.sce');
+datafile=WD+filesep()+'11_06_example.sci';
+clc;
+exec(datafile)
+//unit conversions
+D = D / 100; //from [cm] to [m]
+V = V / 3.6 //from [km/h] to [m/s]
+P = P * 1.01325 * 10**5; //from [atm] to [Pa]
+T = T + 273; //from [C] to [K]
+rho_air = P / (R * T); //from ideal gas equation
+A = %pi / 4 * D**2; //frontal area of ball
+omega = 2 * %pi * N / 60; //angular velocity of ball [rad/s]
+nd_rotation = omega * D /(2 * V); //non dimensional rate of rotation
+//from figure 11-53 lift coefficient coefficient corresponding to nd_rotation is
+C_L = 0.21;
+F_L = C_L * A * rho_air * V**2 / 2; //drag force
+W = m * g;
+if W > F_L then
+ printf("Ball will drop under the combined effect of gravity and lift due to spinning with net force of %1.3f - %1.3f = %1.3f N", W, F_L, W - F_L);
+else
+ printf("Ball will rise under under the combined effect of gravity and lift due to spinning with net force of %1.3f - %1.3f = %1.3f N", F_L, W, F_L - W);
+end