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+// Scilab code Exa5.2.1: To calculate the energy and no. of collision required to stop collision : P.no. 223 (2011)
+m = 511; // Mass of electron, KeV
+M = 938*10^3; // Mass of incident charged particle, KeV
+E = 10*10^3; // Energy of proton, KeV
+E_l = 4*m*E/M; // Energy lost during collison, KeV
+n = E/E_l; // Number of collisions, 
+N = round(n)
+printf("\n The energy lost during collision  = %5.2f KeV \n Number of collision required   = %d collisions",E_l, N )
+// Result
+//     The energy lost during collision  = 21.79 KeV 
+//  Number of collision required   = 459 collisions  
+\ No newline at end of file