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+// Scilab Code Ex 1.6 Calculating Unit cell dimensions: Page-9 (2010)
+d = 2.7D+03;    // Density of fcc structure of aluminium, kg per metre cube
+M = 26.98D-03;     // Atomic weight of aluminium, kg per mole
+n = 4;       // No. of atoms per unit cell of fcc lattice structure of  aluminium
+N = 6.023D+23;    // Avogadro's No.
+// Volume of the unit cell is given by
+// a^3 = M*n/(N*d)
+// Solving for a
+a = ((M*n)/(N*d))^(1/3);    // Lattice parameter of alumitnium unit cell
+// For an fcc cryatal lattice, 
+// 2^(1/2) = 4R = 2D
+// Solving for D
+D = (a/2^(1/2)); // Diameter of aluminium atom
+disp (a/1D-10, "The Lattice parameter of aluminium, in angstrom, is : ");
+disp(D/1D-10, "The diameter of aluminium atom, in angstrom, is : ");
+
+// Result 
+// The Lattice parameter of aluminium, in angstrom, is :
+//     4.0486332
+// The diameter of aluminium atom, in angstrom, is :
+//     2.862816  
+\ No newline at end of file