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+// Scilab Code Ex 1.6 Calculating Unit cell dimensions: Page-9 (2010)

+d = 2.7D+03;    // Density of fcc structure of aluminium, kg per metre cube

+M = 26.98D-03;     // Atomic weight of aluminium, kg per mole

+n = 4;       // No. of atoms per unit cell of fcc lattice structure of  aluminium

+N = 6.023D+23;    // Avogadro's No.

+// Volume of the unit cell is given by

+// a^3 = M*n/(N*d)

+// Solving for a

+a = ((M*n)/(N*d))^(1/3);    // Lattice parameter of alumitnium unit cell

+// For an fcc cryatal lattice, 

+// 2^(1/2) = 4R = 2D

+// Solving for D

+D = (a/2^(1/2)); // Diameter of aluminium atom

+disp (a/1D-10, "The Lattice parameter of aluminium, in angstrom, is : ");

+disp(D/1D-10, "The diameter of aluminium atom, in angstrom, is : ");

+

+// Result 

+// The Lattice parameter of aluminium, in angstrom, is :

+//     4.0486332

+// The diameter of aluminium atom, in angstrom, is :

+//     2.862816  
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