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+clear
+clc
+//Example 3.12 BUOYANT FORCE ON A METAL PART
+//dimensions of wooden block
+l=50; //[mm]
+b=50; //[mm]
+h=10; //[mm]
+y=7.5; //submerged height[mm]
+V=l*b*y //volume of block submerged[mm^3]
+g_w=9800; //specific weight of water[N/m^3]
+Fb1=g_w*V*10^(-9) //buoyant force[N], (factor 10^(-9)m^3/mm^3)
+S1=0.3;
+V1=l*b*h //volume of block[mm^3]
+W1=g_w*S1*V1*10^(-9) //weight of block[N]
+T=Fb1-W1 //tension in cord[N]
+printf("\n The tension in the cord = %.3f N.\n",T)
+
+V2=6600; //volume of metal[mm^3]
+Fb2=g_w*V2*10^(-9) //buoyant force[N]
+//Equilibrium equation, W2-T-Fb2=0 
+g=9.81; //[m/s^2]
+W2=T+Fb2 //weight of metal[N]
+m2=W2*10^3/g //mass of metal[gm](factor 10^3g/1kg)
+printf("\n The mass of metal part = %.1f grams.\n",m2)
+\ No newline at end of file