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+//Problem 13.13: Use Norton’s theorem to determine the current I flowing in the 4 ohm resistance shown in Figure 13.35(a).
+
+//initializing the variables:
+V1 = 4; // in volts
+V2 = 2; // in volts
+R1 = 2; // in ohms
+R2 = 1; // in ohms
+R3 = 4; // in ohms
+
+//calculation:
+//The 4ohm resistance branch is short-circuited as shown in Figure 13.35(b).
+//Figure 13.35(b)
+Isc = V1/R1 + V2/R2
+//the resistance ‘looking-in’ at a break made between A and B is given by
+r = R1*R2/(R1 + R2)
+//From the Norton equivalent network shown in Figure 13.35(c) the current in the 4ohm resistance is given by:
+I = (r/(r + R3))*Isc
+
+printf("\n\n Result \n\n") 
+printf("\n the current in the 4ohm resistance is given by %.3f A",I)
+\ No newline at end of file