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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH13/EX13.13 | |
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Diffstat (limited to '608/CH13/EX13.13')
-rwxr-xr-x | 608/CH13/EX13.13/13_13.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/608/CH13/EX13.13/13_13.sce b/608/CH13/EX13.13/13_13.sce new file mode 100755 index 000000000..775953891 --- /dev/null +++ b/608/CH13/EX13.13/13_13.sce @@ -0,0 +1,20 @@ +//Problem 13.13: Use Norton’s theorem to determine the current I flowing in the 4 ohm resistance shown in Figure 13.35(a).
+
+//initializing the variables:
+V1 = 4; // in volts
+V2 = 2; // in volts
+R1 = 2; // in ohms
+R2 = 1; // in ohms
+R3 = 4; // in ohms
+
+//calculation:
+//The 4ohm resistance branch is short-circuited as shown in Figure 13.35(b).
+//Figure 13.35(b)
+Isc = V1/R1 + V2/R2
+//the resistance ‘looking-in’ at a break made between A and B is given by
+r = R1*R2/(R1 + R2)
+//From the Norton equivalent network shown in Figure 13.35(c) the current in the 4ohm resistance is given by:
+I = (r/(r + R3))*Isc
+
+printf("\n\n Result \n\n")
+printf("\n the current in the 4ohm resistance is given by %.3f A",I)
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