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-rwxr-xr-x462/CH5/EX5.1/ex_5_1.pdfbin0 -> 87413 bytes
-rwxr-xr-x462/CH5/EX5.1/ex_5_1.sce14
-rwxr-xr-x462/CH5/EX5.2/ex_5_2.pdfbin0 -> 84873 bytes
-rwxr-xr-x462/CH5/EX5.2/ex_5_2.sce13
-rwxr-xr-x462/CH5/EX5.3/ex_5_3.pdfbin0 -> 84985 bytes
-rwxr-xr-x462/CH5/EX5.3/ex_5_3.sce14
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diff --git a/462/CH5/EX5.1/ex_5_1.pdf b/462/CH5/EX5.1/ex_5_1.pdf
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+//exmaple 5.1(c)//
+//simplification of an equation//
+clc
+//clears the screen//
+clear
+//clears already existing variables//
+disp('given=> Y=(A+BC)(B+C''A)')
+//given in the question//
+disp('on multiplication we get')
+disp('Y=AB+AC''+BC')
+disp('on further simplification we get')
+disp('BC+AC''')
+//answer after simplification//
+//as per theorem 1.19 given in the question// \ No newline at end of file
diff --git a/462/CH5/EX5.2/ex_5_2.pdf b/462/CH5/EX5.2/ex_5_2.pdf
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+//example 5.2//
+clc
+//clears the screen//
+clear
+//clears already existing variables//
+//conversion of given equation to its canonical SOP form//
+disp('given=> Y=(AB+AC''+BC)')
+disp('on solving')
+disp('Y=AB(C+C'')+AC''(B+B'')+BC(A+A'')')
+disp('Y=ABC+ABC''+ABC''+AB''C''+ABC+A''BC')
+disp('Y=ABC+ABC''+AB''C''+A''BC')
+//using theorem 1.5//
+//result// \ No newline at end of file
diff --git a/462/CH5/EX5.3/ex_5_3.pdf b/462/CH5/EX5.3/ex_5_3.pdf
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+//example 5.3//
+clc
+//clears the screen//
+clear
+//clears already existing variables//
+//conversion of given equation to its canonical POS form//
+disp('given=> Y=(A+B)(A+C)(B+C'')')
+disp('on solving')
+disp('Y=(A+B+CC'')(A+BB''+C)(AA''+B+C'')')
+disp('Y=(A+B+C)(A+B+C'')(A+C+B)(A+C+B'')(A+B+C'')(A''+B+C'')')
+//using theorem 1.10//
+disp('Y=(A+B+C)(A+B+C'')(A+B''+C)(A''+B+C'')')
+//using theorem 1.6//
+//result// \ No newline at end of file