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+//Calculate the efficiency of machine when running as generator and motor
+//Chapter 2
+//Example 2.29
+//page 145
+clear;
+clc; 
+disp("Example 2.29")
+I=440;......................//input at no-load in watt
+V=220;........................//voltage in volts
+Ic=I/V;......................//input current at no-load in amperes
+i=1;....................//input current in amperes
+A=2;.......................//current in amperes
+C=A-i;.....................//armature current at no-load in amperes
+L=I-((((C)^2)*0.5)+(V*C));.................//iron,friction and windage losses in watt
+a=40;...................//motor current in amperes
+OP=(V*a);
+Ra=0.5;
+Effi=(OP*100)/(OP+(((a+i)^2)*Ra)+(V*i)+L)
+printf("Efficiency as a generator when delivering 40A at 220V=%fpercent",Effi)
+Eff=((OP-(((a-i)^2)*Ra)-(V*C)-L)/OP)*100;
+printf("\nEfficiency as a motor when taking 40A from at 220V=%fpercent",Eff)
+\ No newline at end of file