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-rw-r--r--3886/CH18/EX18.1/18_1.sce12
-rw-r--r--3886/CH18/EX18.1/18_1.txt5
-rw-r--r--3886/CH18/EX18.11/18_11.sce18
-rw-r--r--3886/CH18/EX18.11/18_11.txt6
-rw-r--r--3886/CH18/EX18.12/18_12.sce14
-rw-r--r--3886/CH18/EX18.12/18_12.txt4
-rw-r--r--3886/CH18/EX18.13/18_13.sce11
-rw-r--r--3886/CH18/EX18.13/18_13.txt4
-rw-r--r--3886/CH18/EX18.2/18_2.sce9
-rw-r--r--3886/CH18/EX18.2/18_2.txt5
-rw-r--r--3886/CH18/EX18.3/18_3.sce14
-rw-r--r--3886/CH18/EX18.3/18_3.txt6
-rw-r--r--3886/CH18/EX18.4/18_4.sce13
-rw-r--r--3886/CH18/EX18.4/18_4.txt5
-rw-r--r--3886/CH18/EX18.5/18_5.sce22
-rw-r--r--3886/CH18/EX18.5/18_5.txt7
-rw-r--r--3886/CH18/EX18.6/18_6.sce21
-rw-r--r--3886/CH18/EX18.6/18_6.txt7
-rw-r--r--3886/CH18/EX18.7/18_7.sce15
-rw-r--r--3886/CH18/EX18.7/18_7.txt5
-rw-r--r--3886/CH18/EX18.8/18_8.sce17
-rw-r--r--3886/CH18/EX18.8/18_8.txt5
22 files changed, 225 insertions, 0 deletions
diff --git a/3886/CH18/EX18.1/18_1.sce b/3886/CH18/EX18.1/18_1.sce
new file mode 100644
index 000000000..bec05db58
--- /dev/null
+++ b/3886/CH18/EX18.1/18_1.sce
@@ -0,0 +1,12 @@
+//Direct central impact
+//Refer fig. 18.3
+u1=6 //m/sec
+u2=-10 //m/sec
+//Principle of conservation of momentum
+//2*v1+v2=2
+//From the defination of coefficient of restitution
+//v2-v1=12.8
+//solving
+v1=-3.6 //m/sec
+v2=12.8-(-v1) //m/sec
+printf("\nv1=%.2f m/sec\nv2=%.2f m/sec",v1,v2)
diff --git a/3886/CH18/EX18.1/18_1.txt b/3886/CH18/EX18.1/18_1.txt
new file mode 100644
index 000000000..b151eecff
--- /dev/null
+++ b/3886/CH18/EX18.1/18_1.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.1.sce', -1)
+
+v1=-3.60 m/sec
+v2=9.20 m/sec \ No newline at end of file
diff --git a/3886/CH18/EX18.11/18_11.sce b/3886/CH18/EX18.11/18_11.sce
new file mode 100644
index 000000000..8304cbd87
--- /dev/null
+++ b/3886/CH18/EX18.11/18_11.sce
@@ -0,0 +1,18 @@
+//Ball dropped from height
+//refer fig. 18.11
+g=9.81 //m/sec^2
+h0=1.2 //m
+uy=sqrt(2*g*h0) //downward
+h1=1 //m
+v1y=sqrt(2*9.81*h1) //upwards
+e=sqrt(1/1.2)
+//Time of flight
+t1=(2*sqrt(2*9.81*1))/(9.81) //sec
+ux=0.4/0.903 //m/sec
+//Vertical component of velocity after second bounce
+v2y=0.903*sqrt(2*9.81*1) //m/sec
+h2=((v2y)^2)/(2*9.81) //m
+t2=(2*4)/(9.81) //sec
+//Horizontal range
+D2=0.443*0.815 //m
+printf("\ne=%.3f \nh2=%.3f m \nD2=%.3f m ",e,h2,D2)
diff --git a/3886/CH18/EX18.11/18_11.txt b/3886/CH18/EX18.11/18_11.txt
new file mode 100644
index 000000000..529e046b6
--- /dev/null
+++ b/3886/CH18/EX18.11/18_11.txt
@@ -0,0 +1,6 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.11.sce', -1)
+
+e=0.913
+h2=0.815 m
+D2=0.361 m \ No newline at end of file
diff --git a/3886/CH18/EX18.12/18_12.sce b/3886/CH18/EX18.12/18_12.sce
new file mode 100644
index 000000000..ef9595f61
--- /dev/null
+++ b/3886/CH18/EX18.12/18_12.sce
@@ -0,0 +1,14 @@
+//Sphere
+//refere fig. 18.12
+u1=3 //m/sec
+u2=0.6 //m/sec
+//From principle of conservation of momentum
+//v1+5*v2=6
+//From the defination of coefficient of restitution
+//v2-v1=1.8
+//solving
+v1=6-1.3*5 //m/sec
+//The velocity of first ball is reversed after impact
+//Loss of K.E.=Initial K.E.-final K.E.
+loss=1.07 //joules
+printf("\nLoss=%.3f joules",loss)
diff --git a/3886/CH18/EX18.12/18_12.txt b/3886/CH18/EX18.12/18_12.txt
new file mode 100644
index 000000000..96348bb34
--- /dev/null
+++ b/3886/CH18/EX18.12/18_12.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.12.sce', -1)
+
+Loss=1.070 joules \ No newline at end of file
diff --git a/3886/CH18/EX18.13/18_13.sce b/3886/CH18/EX18.13/18_13.sce
new file mode 100644
index 000000000..8b364d5fe
--- /dev/null
+++ b/3886/CH18/EX18.13/18_13.sce
@@ -0,0 +1,11 @@
+//Loss in K.E.
+uAX=7.79 //m/sec
+uBX=-6 //m/sec
+vAX=-5.31 //m/sec
+vBX=7.104 //m/sec
+//mass of the ball m
+m=10/9.81
+//Loss of K.E.
+loss=(10*((7.79^2)+(6*6)-(5.31*5.31)-(7.104*7.104)))/(2*9.81) //J
+printf("\nLoss of K.E.=%.3f J",loss)
+//The answer provided in the textbook is wrong
diff --git a/3886/CH18/EX18.13/18_13.txt b/3886/CH18/EX18.13/18_13.txt
new file mode 100644
index 000000000..01fca8cb6
--- /dev/null
+++ b/3886/CH18/EX18.13/18_13.txt
@@ -0,0 +1,4 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.13.sce', -1)
+
+Loss of K.E.=9.185 J \ No newline at end of file
diff --git a/3886/CH18/EX18.2/18_2.sce b/3886/CH18/EX18.2/18_2.sce
new file mode 100644
index 000000000..ccd33e2df
--- /dev/null
+++ b/3886/CH18/EX18.2/18_2.sce
@@ -0,0 +1,9 @@
+//Body moving to the right
+v2=3 //m/sec
+u2=-10 //m/sec
+v2=4 //m/sec
+//Applying principles of conservation of momentum
+v1=((80*3)-100-40)/(80) //m/sec
+//Defination of coeff. of restitution gives
+e=(4-1.25)/(3+10)
+printf("\nv1=%.3f m/sec\ne=%.3f ",v1,e)
diff --git a/3886/CH18/EX18.2/18_2.txt b/3886/CH18/EX18.2/18_2.txt
new file mode 100644
index 000000000..7c9afcc00
--- /dev/null
+++ b/3886/CH18/EX18.2/18_2.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.2.sce', -1)
+
+v1=1.250 m/sec
+e=0.212 \ No newline at end of file
diff --git a/3886/CH18/EX18.3/18_3.sce b/3886/CH18/EX18.3/18_3.sce
new file mode 100644
index 000000000..74427d055
--- /dev/null
+++ b/3886/CH18/EX18.3/18_3.sce
@@ -0,0 +1,14 @@
+//A golf ball
+h0=10 //m
+//u1=sqrt(2*g*h0)
+u2=0
+v2=0
+//defination of coefficient of restitution gives
+//v1=%e*sqrt(2*g*h0) in upward direction
+//From kinematic equation
+h1=10*0.894^2 //m
+//After second bounce
+h2=6.388 //m
+//After third bounce
+h3=5.105 //m
+printf("\nh1=%.3f m\nAfter second bounce h2=%.3f m\nAfter third bounce h3=%.3f m",h1,h2,h3)
diff --git a/3886/CH18/EX18.3/18_3.txt b/3886/CH18/EX18.3/18_3.txt
new file mode 100644
index 000000000..ff717eafa
--- /dev/null
+++ b/3886/CH18/EX18.3/18_3.txt
@@ -0,0 +1,6 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.3.sce', -1)
+
+h1=7.992 m
+After second bounce h2=6.388 m
+After third bounce h3=5.105 m \ No newline at end of file
diff --git a/3886/CH18/EX18.4/18_4.sce b/3886/CH18/EX18.4/18_4.sce
new file mode 100644
index 000000000..97d3dc681
--- /dev/null
+++ b/3886/CH18/EX18.4/18_4.sce
@@ -0,0 +1,13 @@
+//Ball is dropped from height
+u1=sqrt(2*9.81*1) //m/sec
+v1=-sqrt(2*9.81*0.810) //m/sec
+//There is no movement of the floor before and after striking
+//u2=0
+//v2=0
+//From the defination of coefficient of restitution
+e=(3.987/4.429)
+//Let the velocity of the ball after second bounce be v2
+v2=e*3.987 //m/sec upward
+//Expected height h2
+h2=(3.576^2)/(2*9.81) //m
+printf("\nCoefficient of restitution=%.3f \nExpected height of second bounce h2=%.4f m",e,h2)
diff --git a/3886/CH18/EX18.4/18_4.txt b/3886/CH18/EX18.4/18_4.txt
new file mode 100644
index 000000000..ed7b52339
--- /dev/null
+++ b/3886/CH18/EX18.4/18_4.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.4.sce', -1)
+
+Coefficient of restitution=0.900
+Expected height of second bounce h2=0.6518 m \ No newline at end of file
diff --git a/3886/CH18/EX18.5/18_5.sce b/3886/CH18/EX18.5/18_5.sce
new file mode 100644
index 000000000..c7f2d06c1
--- /dev/null
+++ b/3886/CH18/EX18.5/18_5.sce
@@ -0,0 +1,22 @@
+//Ball in frictionless tube
+//refer fif. 18.4
+u1=sqrt(2*9.81*2) //m/sec
+u2=0
+//By principle of conservation of momentum
+//v1+2*v2=6.264
+//From defination of coefficient of restitution
+//case(1)-e=1
+//v2-v1=6.264
+//solving
+v2=4.176 //m/sec
+v1=6.264-(2*4.176) //m/sec
+//Let h be the height to which hanging ball will rise
+//Change in K.E=Work Done
+h=(v2^2)/(2*9.81) //m
+//case(2)- e=0.7
+//v2-v1=4.385
+//solving
+bv2=(6.264+4.385)/(3) //m/sec
+//Height to which ball will rise
+h2=(bv2^2)/(2*9.81) //m
+printf("\nCase(1)-\nh=%.4f m\nCase(2)-\nh2=%.4f m ",h,h2)
diff --git a/3886/CH18/EX18.5/18_5.txt b/3886/CH18/EX18.5/18_5.txt
new file mode 100644
index 000000000..0c940a833
--- /dev/null
+++ b/3886/CH18/EX18.5/18_5.txt
@@ -0,0 +1,7 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.5.sce', -1)
+
+Case(1)-
+h=0.8888 m
+Case(2)-
+h2=0.6422 m \ No newline at end of file
diff --git a/3886/CH18/EX18.6/18_6.sce b/3886/CH18/EX18.6/18_6.sce
new file mode 100644
index 000000000..ddd12ae7e
--- /dev/null
+++ b/3886/CH18/EX18.6/18_6.sce
@@ -0,0 +1,21 @@
+//Two identical balls
+//refer fig. 18.5 and 18.6 (a) and (b)
+//Before impact
+uAY=4.5 //m/sec
+uAX=7.794 //m/sec
+uBY=10.392 //m/sec
+uBX=-6 //m/sec
+vAY=uAY //m/sec
+vBY=uBY //m/sec
+//Applying principle of conservation of momentum
+//vAX+vBX=1.794
+//From defination of coefficient of restitution
+//vBX-vAX=12.415
+//Solving
+vBX=(12.415+1.794)/(2) //m/sec
+vAX=1.794-7.104 //m/sec
+vA=sqrt((5.31^2)+(4.5^2)) //m/sec
+thetaA=atand(4.5/5.31) //degree
+vB=sqrt((7.104^2)+(10.392^2)) //m/sec
+thetaB=atand(10.392/7.104) //degree
+printf("\nvA=%.3f m/sec\nthetaA=%.3f degree\nvB=%.3f m/sec\nthetaB=%.3f degree",vA,thetaA,vB,thetaB)
diff --git a/3886/CH18/EX18.6/18_6.txt b/3886/CH18/EX18.6/18_6.txt
new file mode 100644
index 000000000..f65b21b53
--- /dev/null
+++ b/3886/CH18/EX18.6/18_6.txt
@@ -0,0 +1,7 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.6.sce', -1)
+
+vA=6.960 m/sec
+thetaA=40.280 degree
+vB=12.588 m/sec
+thetaB=55.643 degree \ No newline at end of file
diff --git a/3886/CH18/EX18.7/18_7.sce b/3886/CH18/EX18.7/18_7.sce
new file mode 100644
index 000000000..ff68f5661
--- /dev/null
+++ b/3886/CH18/EX18.7/18_7.sce
@@ -0,0 +1,15 @@
+//Ball is dropped
+//refer fig. 18.7
+//Normal to line of impact
+u1x=1.986 //m/sec
+//In the line of impact
+u1y=-7.411 //m/sec
+//Let the velocity after impact be v1
+v1x=u1x
+//Initial and final velocities of floor=0
+//From the defination of coefficient of restitution
+v1y=sqrt((1.986^2)+(5.929^2)) //m/sec
+theta=atand(v1x/v1y) //degree to the line of impact
+//Inclination to the plane
+I=90-18.52 //degree The answer provided in the textbook is wrong
+printf("\nv1=%.3f m/sec\nInclination to the plane=%.3f degree",v1,I)
diff --git a/3886/CH18/EX18.7/18_7.txt b/3886/CH18/EX18.7/18_7.txt
new file mode 100644
index 000000000..5e8967ca4
--- /dev/null
+++ b/3886/CH18/EX18.7/18_7.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.7.sce', -1)
+
+v1=6.253 m/sec
+Inclination to the plane=71.480 degree \ No newline at end of file
diff --git a/3886/CH18/EX18.8/18_8.sce b/3886/CH18/EX18.8/18_8.sce
new file mode 100644
index 000000000..71f747103
--- /dev/null
+++ b/3886/CH18/EX18.8/18_8.sce
@@ -0,0 +1,17 @@
+//Ball falls vertically
+//refer fig. 18.8
+//Velocity of the ball which striking plane=3*g
+//Component of velocity down the plane=3*g*sind(20)
+//Component of velocity in the line of impact before striking
+//vy=-3*g*cosd(20)
+//velocity after the impact after striking plane
+//vy=2.4*g*cosd(20)
+//Acceleration in the line of impact=-g*cosd(20)
+//Using kinematic equation
+t=4.8 //sec
+//vx=3*g*sind(20)
+//Acceleration in this direction=g*sind(20)
+//Distance travelled in 4.8 sec
+s=(3*9.81*t*sind(20))-((9.81*t*t*sind(20))/(2)) //m The answer provided in the textbook is wrong
+printf("\nt=%.4f sec\ns=%.4f m",t,s)
+
diff --git a/3886/CH18/EX18.8/18_8.txt b/3886/CH18/EX18.8/18_8.txt
new file mode 100644
index 000000000..b4f27fea6
--- /dev/null
+++ b/3886/CH18/EX18.8/18_8.txt
@@ -0,0 +1,5 @@
+
+--> exec('E:\My program EM\18. Impact of elastic bodies\18.8.sce', -1)
+
+t=4.8000 sec
+s=9.6630 m \ No newline at end of file
generated by cgit (git 2.34.1) at 2024-12-22 09:50:29 +0000