diff options
Diffstat (limited to '3875/CH10/EX10.13')
| -rw-r--r-- | 3875/CH10/EX10.13/10_13.sce | 15 |
1 files changed, 8 insertions, 7 deletions
diff --git a/3875/CH10/EX10.13/10_13.sce b/3875/CH10/EX10.13/10_13.sce index 366e8ace0..d926d115f 100644 --- a/3875/CH10/EX10.13/10_13.sce +++ b/3875/CH10/EX10.13/10_13.sce @@ -8,19 +8,20 @@ W=4.2 //work function in Joule c=3*10^8 //velocity of light in m/s
//calculation
-E=(h*v)/(lambda)//energy in J
+E=(h*c)/(lambda)//energy in J
E_v=E/e //energy in eV
//case (1)
+//(a)
E_k=E_v-W
-mprintf("\nThe kinetic energy of the fastest electrons is = %d eV\n",E_k)
+mprintf("The kinetic energy of the fastest electrons is = %d eV\n",E_k)
+
+//(b)
+mprintf("The kinetic energy of slowest electrons is zero. As the emitted electrons have all possible energies from 0 to certain maximun value is E_k = %d eV \n",E_k)
//case(2)
-mprintf("\nThe kinetic energy of slowest electrons is zero.As the emitted electrons have all possible energies from 0 to certain maximun value is E_k\n")
+mprintf("If V_s is the stopping potential then E_k=e*V_s.Since the electrons have a maximum kinetic energy of %d eV,the stopping potential is also E_k = %d eV \n",E_k,E_k)
//case(3)
-mprintf("If V_s is the stopping potential then E_k=e*V_s.Since the electrons have a maximum kinetoc energy of 2eV,the stopping potential is 2V.\n")
-
-//case(4)
lambda_0=(h*c)/(W*e)
-mprintf("The cut off wavelength for aluminium is %1.2e m",lambda_0) //The answer provided in the textbook is wrong.
+mprintf("The cut off wavelength for aluminium is %1.1e m",lambda_0)
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