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+//===========================================================================
+//chapter 6 example 18
+
+clc;
+clear all;
+
+//variable declraration
+Ts = 300; //number of turns in secondary winding
+Tp = 1; //number of turns in primary winding
+Is =5; //current in A
+Zs =(1.5)+(%i*1) //secondary impedance ‎Ω
+MMF = 100;
+Pi = 1.2; //iron loss in watts
+KN = 300; //turn ratio
+
+
+//calculations
+KT =Ts/Tp; //turn ratio
+Es = Is*Zs; //secondary voltage in volts
+Es1 = sqrt(((real(Es))^2)+((imag(Es))^2));
+Im =MMF/Tp; //magnetising current in A
+E = Pi/Es1; //energy compnent of exciting current on secondary side in A
+Ie = KT*E; //energy compnent of exciting current on primary side in A
+I0 = Im+%i*Ie; //exciting current on primary side in A
+I01 =sqrt(((real(I0))^2)+((imag(I0))^2));
+alpha = atan(Ie/Im);
+alpha1 = (alpha*180)/%pi;
+theta = atan(imag(Zs)/real(Zs));
+theta1 = (theta*180)/%pi;
+KC = KT+((I01*sin(((theta1+alpha1)*%pi)/180))/Is); //actual current ratio
+e = ((KN-KC)/KC)*100; //percentage ratio error in %
+b = (I01*cos((((theta1+alpha1)*%pi)/180)))/(KT*Is); //phase angle in radians
+b1 = b*(180/%pi);
+
+
+//result
+mprintf("percentage ratio error =%3.2f percentage ",e);
+mprintf("\nphase angle = %3.2f °",b1);
+
+