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+//===========================================================================
+//chapter 10 example 11
+
+clc;clear all;
+
+//variable declaration
+P = 1000; //resistance in arm AC in Ω
+Q = 1000; //resistance in arm AD in Ω
+S = 100; //resistance in arm CB in Ω
+R = 101; //resistance in arm BD in Ω
+Rg = 50; //galvanometer resistance in Ω
+E = 2; //voltage in V
+
+//calculations
+R1 = (Q*S)/P; //resistance required in arm BD for balance bridge
+dR = R-R1; //the deviation from balanced condition in Ω
+Eth = E*(((R1+dR)/(R1+dR+S))-(P/(P+Q))); //thevenin's open circuit voltage in V
+Rth = (((R1+dR)*S)/(R1+dR+S))+((P*Q)/(P+Q)); //thevenin's equivalent resistance of bridge in Ω
+Ig = Eth/(Rth+Rg); //galvanometer current in A
+
+//result
+mprintf("galvanometer current = %3.3f uA",(Ig*10^6));
+mprintf("\nsince the point B is at higher potential with respect to point A ,current will floe from terminal A");