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diff --git a/3864/CH8/EX8.14/Ex8_14.sce b/3864/CH8/EX8.14/Ex8_14.sce
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+clear
+//
+//
+
+//Initilization of Variables
+
+d_o=300 //mm //Outside diameter 
+d1=180 //mm //Internal Diameter
+p=12 //N/mm**2 //internal Fluid pressure
+p_o=6 //N/mm**2 //External Pressure
+r_o=150 //mm //Outside Diameter
+r=90 //mm //Internal Diameter
+
+
+//Calculations
+
+//From Lame's Equation we have
+//p_x=b*(x**2)**-1-a       ..........................(1)
+//F_x=b*(x**2)**-1+a      ...........................(2)
+
+//At 
+x=90 //N/mm**2 
+r1=90 //N/mm**2 
+p=42 //N/mm**2
+//Sub in equation 1 we get
+//42=b*(90**2)**-1-a       ..............................(3)
+
+//At 
+p2=6 //N/mm**2
+//sub in equation 1 we get
+//6=b*(150**2)**-1-a   ..............................(4)
+
+//From equations 3 and 4  weget
+//36=b*(90**2)**-1-b2(150**2)**-1
+//After further simplifying we get
+b=36*90**2*150**2*(150**2-90**2)**-1
+
+//Sub value of b in equation 4 we get
+a=b*(150**2)**-1-p_o
+
+//At 
+F_x=b*(x**2)**-1+a //N/mm**2
+
+//At 
+x2=150 //mm 
+r=150 //mm 
+
+F_x2=b*(x2**2)**-1+a  //N/mm**2
+
+//Now if External pressure is doubled i.e p_o2=12 //N/mm**2 We have
+p_o2=12 //N/mm**2
+//sub in equation 4 we get
+//12=b2*(150**2)**-1-a2                    ..........................(5)
+
+//Max Hoop stress is to be 70.5 //N/mm**2,which occurs at x=r1=90 //mm
+//Sub in equation 4 we get
+//70.5=b*(90**2)**-1+a2           ................................(6)
+
+//Adding equation 5 and 6
+//82.5=b2*(150**2)**-1+b*(90**2)**-1
+//After furhter simplifying we get
+b2=82.5*150**2*90**2*(150**2+90**2)**-1
+
+//Sub in equation 5 we get
+a2=b2*(150**2)**-1-12 
+
+//If p_i is the internal pressure required then from Lame's theorem
+p_i=b2*(r1**2)**-1-a2
+
+//Result
+printf("\n Stresses int the material are:F_x %0.2f  N/mm**2",F_x)
+printf("\n                              :F_x2 %0.2f  N/mm**2",F_x2)
+printf("\n Internal Pressure that can be maintained is %0.2f  N/mm**2",p_i)