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+clear
+//
+//
+
+//Initilization of Variables
+
+d=75 //mm //diameter
+P=30*10**6 //W //Power transmitted
+W=6 //N-mm/sec //Load
+L=1000 //mm
+N=300 //r.p.m
+
+//Calculations
+
+//B.M
+M=W*L*4**-1 //N-mm
+T=P*60*(2*%pi*N)**-1 //Torque transmitted
+
+//M.I
+I=%pi*64**-1*d**4 //mm**4
+
+//Bending stress
+f_A=M*I**-1*(d*2**-1) //N/mm**2
+
+//At A
+p_x=f_A
+p_y=0
+
+//Polar Modulus
+J=%pi*32**-1*d**4 //mm**4
+
+//Shearing stress
+q=T*J**-1*(d*2**-1) //N/mm**2
+
+//Principal Stresses
+P1=(p_x+p_y)*2**-1+(((p_x-p_y)*2**-1)**2+q**2)**0.5 //N/mm**2
+P2=(p_x+p_y)*2**-1-(((p_x-p_y)*2**-1)**2+q**2)**0.5 //N/mm**2
+
+//Max shear stress
+q_max=(((p_x-p_y)*2**-1)**2+q**2)**0.5 //N/mm**2
+
+//Bending stress
+p_x2=0
+p_y2=0
+
+//Shearing stress
+q2=T*J**-1*d*2**-1 //N/mm**2
+
+//Principal stresses
+P3=(p_x2+p_y2)*2**-1+(((p_x2-p_y2)*2**-1)**2+q2**2)**0.5 //N/mm**2
+P4=(p_x2+p_y2)*2**-1-(((p_x2-p_y2)*2**-1)**2+q2**2)**0.5 //N/mm**2
+
+//Max shear stress
+q_max2=(((p_x2-p_y2)*2**-1)**2+q2**2)**0.5 //N/mm**2
+
+//Answer for Principal Stresses P1,P2 and Max stress i.e q_max is incorrect in Book
+
+//Result
+printf("\n Principal Stresses at vertical Diameter:P1 %0.2f N/mm**2",P1)
+printf("\n :P2 %0.2f N/mm**2",P2)
+printf("\n Max stress at vertical Diameter : %0.2f N/mm**2",q_max)
+printf("\n Principal Stresses at Horizontal Diameter:P3 %0.2f N/mm**2",P3)
+printf("\n :P4 %0.2f N/mm**2",P4)
+printf("\n Max stress at Horizontal Diameter : %0.2f N/mm**2",q_max2)