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clear
//
//
//Initilization of Variables
d=75 //mm //diameter
P=30*10**6 //W //Power transmitted
W=6 //N-mm/sec //Load
L=1000 //mm
N=300 //r.p.m
//Calculations
//B.M
M=W*L*4**-1 //N-mm
T=P*60*(2*%pi*N)**-1 //Torque transmitted
//M.I
I=%pi*64**-1*d**4 //mm**4
//Bending stress
f_A=M*I**-1*(d*2**-1) //N/mm**2
//At A
p_x=f_A
p_y=0
//Polar Modulus
J=%pi*32**-1*d**4 //mm**4
//Shearing stress
q=T*J**-1*(d*2**-1) //N/mm**2
//Principal Stresses
P1=(p_x+p_y)*2**-1+(((p_x-p_y)*2**-1)**2+q**2)**0.5 //N/mm**2
P2=(p_x+p_y)*2**-1-(((p_x-p_y)*2**-1)**2+q**2)**0.5 //N/mm**2
//Max shear stress
q_max=(((p_x-p_y)*2**-1)**2+q**2)**0.5 //N/mm**2
//Bending stress
p_x2=0
p_y2=0
//Shearing stress
q2=T*J**-1*d*2**-1 //N/mm**2
//Principal stresses
P3=(p_x2+p_y2)*2**-1+(((p_x2-p_y2)*2**-1)**2+q2**2)**0.5 //N/mm**2
P4=(p_x2+p_y2)*2**-1-(((p_x2-p_y2)*2**-1)**2+q2**2)**0.5 //N/mm**2
//Max shear stress
q_max2=(((p_x2-p_y2)*2**-1)**2+q2**2)**0.5 //N/mm**2
//Answer for Principal Stresses P1,P2 and Max stress i.e q_max is incorrect in Book
//Result
printf("\n Principal Stresses at vertical Diameter:P1 %0.2f N/mm**2",P1)
printf("\n :P2 %0.2f N/mm**2",P2)
printf("\n Max stress at vertical Diameter : %0.2f N/mm**2",q_max)
printf("\n Principal Stresses at Horizontal Diameter:P3 %0.2f N/mm**2",P3)
printf("\n :P4 %0.2f N/mm**2",P4)
printf("\n Max stress at Horizontal Diameter : %0.2f N/mm**2",q_max2)
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