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+clear
+//
+//
+
+//Initilization of Variables
+
+//Direct stresses
+p_x=120 //N/mm**2 //Tensile stress
+p_y=-100 //N/mm**2 //Compressive stress
+p1=160 //N/mm**2 //Major principal stress
+
+//Calculations
+
+//Let q be the shearing stress
+
+//p1=(p_x+p_y)*2**-1+((((p_x+p_y)*2**-1)**2)+q**2)**0.5
+//After further simplifying we get
+q=(p1-((p_x+p_y)*2**-1))**2-((p_x-p_y)*2**-1)**2 //N/mm**2
+q2=(q)**0.5 //N/mm**2
+
+//Minimum Principal stress
+p2=(p_x+p_y)*2**-1-(((p_x-p_y)*2**-1)**2+q2**2)**0.5 //N/mm**2
+
+//Max shearing stress
+q_max=(((p_x-p_y)*2**-1)**2+q2**2)**0.5 //N/mm**2
+
+//Result
+printf("\n Shearing stress of material %0.2f N/mm**2",q)
+printf("\n Min Principal stress %0.2f N/mm**2",p2)
+printf("\n Max shearing stress %0.2f N/mm**2",q_max)