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+clear
+//
+
+//Initilization of Variables
+
+P=200*10**3 //N //Load
+A_a=1000 //mm**2 //Area of Aluminium
+A_s=800 //mm**2 //Area of steel
+E_a=1*10**5 //N/mm**2 //Modulus of Elasticity of Aluminium
+E_s=2*10**5 //N/mm**2 //Modulus of ELasticity of steel
+sigma_a1=65 //N/mm**2 //stress in aluminium
+sigma_s1=150 //N/mm**2 //Stress in steel
+
+//Calculations   
+
+//Let P_a and P_s be the force in aluminium and steel pillar respectively
+
+//Now,sum of forces in Vertical direction we get
+//2*P_a+P_s=200  .........................................(1)
+
+//By compatibility Equation dell_l_s=dell_l_a we get
+//P_s=1.28*P_a  ..........................................(2)
+
+//Now substituting value of P_s in Equation 1 we get
+P_a=200*3.28**-1 //KN
+P_s=200-2*P_a   //KN
+
+//Stress developed in aluminium
+sigma_a=P_a*10**3*A_a**-1 //N/mm**2 
+
+//Stress developed in steel
+sigma_s=P_s*10**3*A_s**-1 //N/mm**2 
+
+//Part-2
+
+//Let sigma_a1 and sigma_s1 be the stresses in Aluminium and steel due to Additional LOad
+
+P_a1=sigma_a1*A_a //Load carrying capacity of aluminium
+P_s1=1.28*P_a1
+
+//Total Load carrying capacity 
+P1=2*P_a1+P_s1 //N 
+
+P_s2=sigma_s1*A_s //Load carrying capacity of steel
+P_a2=P_s2*1.28**-1
+
+//Total Load carrying capacity
+P2=2*P_a2+P_s2
+
+//Additional Load
+P3=P1-P
+
+//Result
+printf("\n Stresses Developed in Each Pillar is:sigma_a %0.2f  N/mm**2",sigma_a)
+printf("\n                                     :sigma_s %0.2f  N/mm**2",sigma_s)
+printf("\n Additional Load taken by pillars is %0.2f  N",P3)