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+clear
+//
+//
+
+//Initilization of Variables
+
+P_e=300 //N/mm**2 //Elastic Limit in tension
+FOS=3 //Factor of safety
+mu=0.3 //Poissons ratio
+P=12*10**3 //N Pull
+Q=6*10**3 //N //Shear force
+
+//Calculations
+
+//Let d be the diameter of the shaft
+
+//Direct stress
+//P_x=P*(%pi*4**-1*d**3)**-1
+//After substituting values and further simplifying we get
+//P_x=48*10**3
+
+//Now shear stress at the centre of bolt
+//q=4*3**-1*q_av
+//After substituting values and further simplifying we get
+//q=32*10**3*(%pi*d**2)**-1
+
+//Principal stresses are
+//P1=P_x*2**-1+((P_x*2**-1)**2+q**2)**0.5
+//After substituting values and further simplifying we get
+//p1=20371.833*(d**2)**-1
+
+//P2=P_x*2**-1-((P_x*2**-1)**2+q**2)**0.5
+//After substituting values and further simplifying we get
+//P2=-5092.984*(d**2)**-1
+
+//q_max=((P_x*2**-1)**2+q**2)**0.5
+
+//From Max Principal stress theory
+//Permissible stress in Tension
+P1=100 //N/mm**2
+d=(20371.833*P1**-1)**0.5
+
+//Max strain theory
+//e_max=P1*E**-1-mu*P2*E**-1
+//After substituting values and further simplifying we get
+//e_max=21899.728*(d**2*E)**-1
+
+//According to this theory,the design condition is
+//e_max=P_e*(E*FOS)**-1
+//After substituting values and further simplifying we get
+d2=(21899.728*3*300**-1)**0.5 //mm
+
+//Max shear stress theory
+//e_max=shear stress at elastic*(FOS)**-1
+//After substituting values and further simplifying we get
+d3=(12732.421*6*300**-1)**0.5 //mm
+
+//Result
+printf("\n Diameter of Bolt by:Max Principal stress theory %0.2f mm",d)
+printf("\n :Max strain theory %0.2f mm",d2)
+printf("\n :Max shear stress theory %0.2f mm",d3)