diff options
Diffstat (limited to '3862/CH8/EX8.23/Ex8_23.sce')
| -rw-r--r-- | 3862/CH8/EX8.23/Ex8_23.sce | 28 |
1 files changed, 28 insertions, 0 deletions
diff --git a/3862/CH8/EX8.23/Ex8_23.sce b/3862/CH8/EX8.23/Ex8_23.sce new file mode 100644 index 000000000..2911ca612 --- /dev/null +++ b/3862/CH8/EX8.23/Ex8_23.sce @@ -0,0 +1,28 @@ +clear +// + +//variable declaration + +// Let the force shared by bolt be Ps and that by tube be Pc. Since there is no external force, static equilibrium condition gives Ps + Pc = 0 or Ps = – Pc i.e., the two forces are equal in magnitude but opposite in nature. Obviously bolt is in tension and tube is in compression. +//Let the magnitude of force be P. Due to quarter turn of the nut + +//[Note. Pitch means advancement of nut in one full turn] + +Ls=(600) //length of whole assembly,mm +Lc=(600) //length of whole assembly,mm +delta=(0.5) +ds=(20) //diameter,mm +di=(28) //internal diameter,mm +de=(40) //external diameter,mm +Es=(2*100000) //Young's modulus, N/mm^2 +Ec=(1.2*100000) +As=%pi*(ds**2)/4 //area of steel bolt**mm^2 +Ac=%pi*((de**2)-(di**2))/4 //area of copper tube**mm^2 + +P= (delta*(1/Ls))/((1/(As*Es))+(1/(Ac*Ec))) //Load,N + +ps=P/As //stress,N/mm^2 +pc=P/Ac //copper,N/mm^2 + +printf("\n ps= %0.2f N/mm^2",ps) +printf("\n pc= %0.2f N/mm^2",pc) |