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clear
//
//variable declaration
// Let the force shared by bolt be Ps and that by tube be Pc. Since there is no external force, static equilibrium condition gives Ps + Pc = 0 or Ps = – Pc i.e., the two forces are equal in magnitude but opposite in nature. Obviously bolt is in tension and tube is in compression.
//Let the magnitude of force be P. Due to quarter turn of the nut
//[Note. Pitch means advancement of nut in one full turn]
Ls=(600) //length of whole assembly,mm
Lc=(600) //length of whole assembly,mm
delta=(0.5)
ds=(20) //diameter,mm
di=(28) //internal diameter,mm
de=(40) //external diameter,mm
Es=(2*100000) //Young's modulus, N/mm^2
Ec=(1.2*100000)
As=%pi*(ds**2)/4 //area of steel bolt**mm^2
Ac=%pi*((de**2)-(di**2))/4 //area of copper tube**mm^2
P= (delta*(1/Ls))/((1/(As*Es))+(1/(Ac*Ec))) //Load,N
ps=P/As //stress,N/mm^2
pc=P/Ac //copper,N/mm^2
printf("\n ps= %0.2f N/mm^2",ps)
printf("\n pc= %0.2f N/mm^2",pc)
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