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Diffstat (limited to '3862/CH2/EX2.29/Ex2_29.sce')
| -rw-r--r-- | 3862/CH2/EX2.29/Ex2_29.sce | 39 |
1 files changed, 39 insertions, 0 deletions
diff --git a/3862/CH2/EX2.29/Ex2_29.sce b/3862/CH2/EX2.29/Ex2_29.sce new file mode 100644 index 000000000..21a9df515 --- /dev/null +++ b/3862/CH2/EX2.29/Ex2_29.sce @@ -0,0 +1,39 @@ +clear +// + + +// Let O1 and O2 be the centres of the first and second spheres. Drop perpendicular O1P to the horizontal line through O2. show free body diagram of the sphere 1 and 2, respectively. Since the surface of contact are smooth, reaction of B is in the radial direction, i.e., in the direction O1O2. Let it make angle a with the horizontal. Then, + +//Variable declaration + +W=100.0 //weight of spheres,N + +r=100.0 //radius of spheres,mm + +d=360.0 // horizontal channel having vertical walls, the distance b/w,mm + +O1A=100.0 +O2D=100.0 +O1B=100.0 +BO2=100.0 + +O2P=360.0-O1A-O2D +O1O2=O1B+BO2 + +alpha=acos(O2P/O1O2) + +//////sum of vertical Fy & sum of horizontal forces Fx is zero +//Assume direction of Fx is right +//Assume direction of Fy is up +RB=W/sin(alpha) +RA=RB*cos(alpha) +printf("\n RB= %0.2f N",RB) +printf("\n RA= %0.2f N",RA) + +RC=100+RB*sin(alpha) + +RD=RB*cos(alpha) + +printf("\n RC= %0.0f N",RC) + +printf("\n RD= %0.2f N",RD) |