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//
// Let O1 and O2 be the centres of the first and second spheres. Drop perpendicular O1P to the horizontal line through O2. show free body diagram of the sphere 1 and 2, respectively. Since the surface of contact are smooth, reaction of B is in the radial direction, i.e., in the direction O1O2. Let it make angle a with the horizontal. Then,
//Variable declaration
W=100.0 //weight of spheres,N
r=100.0 //radius of spheres,mm
d=360.0 // horizontal channel having vertical walls, the distance b/w,mm
O1A=100.0
O2D=100.0
O1B=100.0
BO2=100.0
O2P=360.0-O1A-O2D
O1O2=O1B+BO2
alpha=acos(O2P/O1O2)
//////sum of vertical Fy & sum of horizontal forces Fx is zero
//Assume direction of Fx is right
//Assume direction of Fy is up
RB=W/sin(alpha)
RA=RB*cos(alpha)
printf("\n RB= %0.2f N",RB)
printf("\n RA= %0.2f N",RA)
RC=100+RB*sin(alpha)
RD=RB*cos(alpha)
printf("\n RC= %0.0f N",RC)
printf("\n RD= %0.2f N",RD)
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