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+//Calculate the Collision frequency Binary Collision Number and Mean free path of Nitrogen
+
+//Example 3.2 
+
+clc;
+
+clear;
+
+R=8.314;  //Gas constant in J K^-1 mol^-1
+
+T=298;  //Temperature in Kelvin
+
+mew=0.02800;  //Molar mass of Nitrogen in Kg mol^-1
+
+Cbar=sqrt((8*R*T)/(%pi*mew))*100; //Average speed of Nitrogen in cm/s
+
+Conc=2.5*10^19; //Concentration of dry air in cm^-3
+
+Cd=3.75*10^-8;  //Collision diameter in cm
+
+Z1=sqrt(2)*%pi*(Cd)^2*Cbar*Conc;....//Collision frequency in collisions s^-1
+
+printf("Collision frequency of Nitrogen = %.1f*10^9 collisions s^-1",Z1*10^-9);//(The answers vary due to round off error)
+ 
+Z11=(Z1/2)*Conc;....//Binary Collision number in cm^-3 s^-1
+
+printf("\nBinary collision number = %.1f*10^28 collisions cm^-3 s^-1",Z11*10^-28);
+
+lambda=Cbar/Z1; //Mean free path of Nitrogen in A/collision
+
+printf("\nMean free path of Nirogen = %.0f* A/collision",lambda*10^8);
+