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+//To Determine the value of Km and Vmax of Enzyme and to Calculate Kinetic Paramters imposed by inhibitors
+
+//Example 13.1
+
+clc;
+
+clear;
+
+s=[5*10^-4,1*10^-3,2.5*10^-3,5.0*10^-3,1.0*10^-2];//Substrate Concentration
+
+v0no=[1.25*10^-6,2.0*10^-6,3.13*10^-6,3.85*10^-6,4.55*10^-6];//Initial Rate of an Enzyme Catalysed Concentration with no inhibitor
+
+voA=[5.8*10^-7,1.04*10^-6,2.00*10^-6,2.78*10^-6,3.57*10^-6];//Initial Rate of an Enzyme Catalysed Concentration with inhibitor A
+
+voB=[3.8*10^-7,6.3*10^-7,1.00*10^-6,1.25*10^-6,1.43*10^-6];//Initial Rate of an Enzyme Catalysed Concentration with inhibitor B
+
+for i=1:5
+ Srec(i)=1/s(i);//Calculating the reciprocals of Substrate Concentrations
+end
+
+for i=1:5
+ v0norec(i)=1/v0no(i);//Reciprocal of Initial Rate of an Enzyme Catalysed Concentration with no inhibitor
+end
+
+for i=1:5
+ v0Arec(i)=1/voA(i);//Reciprocal of Initial Rate of an Enzyme Catalysed Concentration with inhibitor A
+end
+
+for i=1:5
+ v0Brec(i)=1/voB(i);//Reciprocal of Initial Rate of an Enzyme Catalysed Concentration with inhibitor B
+end
+
+plot(Srec,v0norec);//Graph between Reciprocal of Substrate Concentration and Reciprocal of Initial Rate of an Enzyme Catalysed Concentration with no inhibitor
+
+m1=(v0norec(2)-v0norec(1))/(Srec(2)-Srec(1));//Slope of 1st Graph
+
+vmax=1/(-m1*Srec(3)+v0norec(3));//Maximum Rate of reaction
+
+Km=m1*vmax;//Maximum value of Kinetic Parameter
+
+printf("The value of vmax=%.2f*10^-6 M s^-1",vmax*10^6);
+
+printf("\nThe value of Km=%.1f*10^-3 M",Km*10^3)
+
+plot(Srec,v0Arec);//Graph between Reciprocal of Substrate Concentration and Reciprocal of Initial Rate of an Enzyme Catalysed Concentration with inhibitor A
+
+m2=(v0Arec(2)-v0Arec(1))/(Srec(2)-Srec(1));//Slope of 2nd Graph
+
+I=8.0*10^-3;//Initial Concentration
+
+K1=I/((m2*vmax/Km)-1);//Kinetic Parameter with Inhibitor A
+
+printf("\nThe value of kinetic parameter with inhibitor A=%.1f*10^-3 M",K1*10^3)
+
+plot(Srec,v0Brec);//Graph between Reciprocal of Substrate Concentration and Reciprocal of Initial Rate of an Enzyme Catalysed Concentration with inhibitor B
+
+m3=(v0Brec(1)-v0Brec(3))/(Srec(1)-Srec(3));//Slope of 3rd Graph
+
+K2=I/((m3*vmax/Km)-1);//Kinetic Parameter with Inhibitor B
+
+printf("\nThe value of kinetic parameter with inhibitor B=%.1f*10^-3 M",K2*10^3)
diff --git a/3856/CH13/EX13.1/Ex13_1.txt b/3856/CH13/EX13.1/Ex13_1.txt
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+ The value of vmax=5.01*10^-6 M s^-1
+The value of Km=1.5*10^-3 M
+The value of kinetic parameter with inhibitor A=5.2*10^-3 M
+The value of kinetic parameter with inhibitor B=3.3*10^-3 M \ No newline at end of file