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+//Calculate the Rate constant for Forward abd Reverse reaction 
+
+//Example 12.4
+
+clc;
+
+clear
+
+Tau=36*10^-6;  //The relaxation time for the system to reach the new equilibrium in s
+
+C1=1.0*10^-7; //Concentration of the Hydrogen ion in M
+
+C2=1.0*10^-7; //Concentration of the Hydroxyl ion in M (C1=C2)
+
+C3=55.5;  //Concentration of the Water in M 
+
+Kf=C3/((Tau)*((C1+C2)*(C3)+(C1*C2)));//Rate constant for Forward reaction in M^-1 s^-1(Kf*C1*C2=Kr*C3)(Tau=1/(Kf*(C1+C2)+Kr)
+
+printf("Rate constant for Forward reaction = %.1f*10^11 M^-1 s^-1",Kf*10^-11);
+
+K=(C1*C2)/C3; //Equilibrium Constant for the reaction in M (Hydrogen ion +Hydroxyl ion=Water )
+
+Kr=Kf*K; //Rate constant for Reverse reaction in s^-1
+
+printf("\n Rate constant for Reverse reaction = %.1f*10^-5 s^-1 ",Kr*10^5);