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-rw-r--r--3843/CH3/EX3.3/Ex3_7.sce20
-rw-r--r--3843/CH4/EX4.9/Ex4_9.sce1
2 files changed, 1 insertions, 20 deletions
diff --git a/3843/CH3/EX3.3/Ex3_7.sce b/3843/CH3/EX3.3/Ex3_7.sce
deleted file mode 100644
index db644a72e..000000000
--- a/3843/CH3/EX3.3/Ex3_7.sce
+++ /dev/null
@@ -1,20 +0,0 @@
-// Example 3_7
-clc;funcprot(0);
-// Given data
-d=50*10^-3;// The distance in m
-K=2500;// N/m
-m=50;// kg
-d_p=10/100;// m
-P_atm=100;// The atmospheric pressure in kPa
-g=9.81;// m/s^2
-
-// Calculation
-W=m*g;// The weight in N
-A=(%pi*d_p^2)/4;// m^2
-P_1=((P_atm*10^3*A)+W)/A;// The pressure in the cylinder in Pa
-W_1=(P_1*A)*d;// J
-x_1=0;// m
-x_2=d;// m
-W_2=(1/2)*K*((x_2^2)-(x_1^2));// The work required to compress in J
-W_total=W_1+W_2;// The total work in J
-printf("\nThe total work,W_total=%2.2f J",W_total);
diff --git a/3843/CH4/EX4.9/Ex4_9.sce b/3843/CH4/EX4.9/Ex4_9.sce
index 32dcb3fff..5aa74f3f9 100644
--- a/3843/CH4/EX4.9/Ex4_9.sce
+++ b/3843/CH4/EX4.9/Ex4_9.sce
@@ -20,3 +20,4 @@ v_2=v_1;// m^3/kg
u_2=((0.6203-0.6181)/(0.6181-0.5601))*(3661-3476);// kJ/kg
Q=m*(u_2-u_1);// kJ
printf("\nThe heat transfer,Q=%4.0f kJ",Q);
+// The answer provided in the textbook is wrong